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	<title>Comments for High Voltage Hot Rods</title>
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	<link>http://www.evmania.com/blog</link>
	<description>Building electric sports cars and hot rods!</description>
	<lastBuildDate>Sat, 24 Sep 2011 18:55:06 +0000</lastBuildDate>
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		<title>Comment on LiPo &#8211; Batteries Terms Explained by admin</title>
		<link>http://www.evmania.com/blog/2011/02/28/lipo-batteries-terms-explained/comment-page-1/#comment-150</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Sat, 24 Sep 2011 18:55:06 +0000</pubDate>
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		<description>Nick,
Thanks for your response. </description>
		<content:encoded><![CDATA[<p>Nick,<br />
Thanks for your response.</p>
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		<title>Comment on LiPo &#8211; Batteries Terms Explained by OldNick</title>
		<link>http://www.evmania.com/blog/2011/02/28/lipo-batteries-terms-explained/comment-page-1/#comment-149</link>
		<dc:creator>OldNick</dc:creator>
		<pubDate>Wed, 07 Sep 2011 03:11:54 +0000</pubDate>
		<guid isPermaLink="false">http://www.evmania.com/blog/?p=1356#comment-149</guid>
		<description>Just want to comment here. I found this site because O was looking at LiPo details

I reckon you have made some incorrect and possibly damaging or dangerous statements above.

&quot;C -How fast a battery can be charged or discharged. A battery with a discharge rating of 2C would mean you could discharge it at a rate 2 times more than the capacity of the pack, a 3C pack = 3 times more, a 20C pack = 20 times more, and so on.&quot;

The C rating is how fast the battery can DIScharge, not be charged. Charging is usually 1 (1 hour charging time),2.... maybe 5C. There m ay be better, but to say the C rate (discharge) is the charge rate is dodgy.

&quot;The higher the C value the higher the cost usually.  What this means to an EV though is how much power you can effectively use.  If the C rating is low, you are going to have to use more cells to increase the voltage so that you use less amperage.&quot;

If the C rating is low, then the _last_ thing you want to do is increase the volts &quot;to use less amperage&quot;: 
--In fact increasing the voltage will _increase_ the amperage (which is actually what you want through the motor to make it faster). While power is a product of volts and amps, increasing volts also increases amps over a given load. You get less amps from more volts and the same power only if the load draws less current at the new volts. Only if things are balanced in that regard, then you would have the same power at less amps.
-- The C rate of batteries is not just about what they can provide the load, due to internal resistance. If you have a C rate of say 20, then that battery will only tolerate a discharge rate of 20 * its AH capacity. It will suffer and maybe burn if you extract much more. LiPos are notorious for this, although now much better protected. That is what would happen if you added more batteries (Volts) without altering the load, to a point where the C rating of the battery was exceeded. This is still caused by internal resistance, which is  creating heat in the battery as current flows.
--If you want to increase the current from batteries that have insufficient discharge rate, you need to leave the volts as they are. The paralleled batteries will share the current, not get hot, and provide easier current to the load. This results in more power for the same load.

Nick</description>
		<content:encoded><![CDATA[<p>Just want to comment here. I found this site because O was looking at LiPo details</p>
<p>I reckon you have made some incorrect and possibly damaging or dangerous statements above.</p>
<p>&#8220;C -How fast a battery can be charged or discharged. A battery with a discharge rating of 2C would mean you could discharge it at a rate 2 times more than the capacity of the pack, a 3C pack = 3 times more, a 20C pack = 20 times more, and so on.&#8221;</p>
<p>The C rating is how fast the battery can DIScharge, not be charged. Charging is usually 1 (1 hour charging time),2&#8230;. maybe 5C. There m ay be better, but to say the C rate (discharge) is the charge rate is dodgy.</p>
<p>&#8220;The higher the C value the higher the cost usually.  What this means to an EV though is how much power you can effectively use.  If the C rating is low, you are going to have to use more cells to increase the voltage so that you use less amperage.&#8221;</p>
<p>If the C rating is low, then the _last_ thing you want to do is increase the volts &#8220;to use less amperage&#8221;:<br />
&#8211;In fact increasing the voltage will _increase_ the amperage (which is actually what you want through the motor to make it faster). While power is a product of volts and amps, increasing volts also increases amps over a given load. You get less amps from more volts and the same power only if the load draws less current at the new volts. Only if things are balanced in that regard, then you would have the same power at less amps.<br />
&#8211; The C rate of batteries is not just about what they can provide the load, due to internal resistance. If you have a C rate of say 20, then that battery will only tolerate a discharge rate of 20 * its AH capacity. It will suffer and maybe burn if you extract much more. LiPos are notorious for this, although now much better protected. That is what would happen if you added more batteries (Volts) without altering the load, to a point where the C rating of the battery was exceeded. This is still caused by internal resistance, which is  creating heat in the battery as current flows.<br />
&#8211;If you want to increase the current from batteries that have insufficient discharge rate, you need to leave the volts as they are. The paralleled batteries will share the current, not get hot, and provide easier current to the load. This results in more power for the same load.</p>
<p>Nick</p>
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		<title>Comment on Home by admin</title>
		<link>http://www.evmania.com/blog/about/comment-page-1/#comment-144</link>
		<dc:creator>admin</dc:creator>
		<pubDate>Thu, 07 Apr 2011 22:43:29 +0000</pubDate>
		<guid isPermaLink="false">http://www.evmania.com/blog/?page_id=2#comment-144</guid>
		<description>Actually no.  That is another site.  I am the builder of the EVGT-40 and have the scars to show for it.</description>
		<content:encoded><![CDATA[<p>Actually no.  That is another site.  I am the builder of the EVGT-40 and have the scars to show for it.</p>
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		<title>Comment on Brakes by faridmi</title>
		<link>http://www.evmania.com/blog/2008/11/17/brakes/comment-page-1/#comment-131</link>
		<dc:creator>faridmi</dc:creator>
		<pubDate>Fri, 20 Aug 2010 08:33:22 +0000</pubDate>
		<guid isPermaLink="false">http://www.evmania.com/blog/2008/11/17/brakes/#comment-131</guid>
		<description>hello 
may I ask  how did you chose your vacuum pump?
thanks for your nice blog</description>
		<content:encoded><![CDATA[<p>hello<br />
may I ask  how did you chose your vacuum pump?<br />
thanks for your nice blog</p>
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	<item>
		<title>Comment on Home by YHTNAPA</title>
		<link>http://www.evmania.com/blog/about/comment-page-1/#comment-130</link>
		<dc:creator>YHTNAPA</dc:creator>
		<pubDate>Sat, 31 Jul 2010 23:04:01 +0000</pubDate>
		<guid isPermaLink="false">http://www.evmania.com/blog/?page_id=2#comment-130</guid>
		<description>As a car guy, I love your site. This is the future of hot rods. Restore not back to OE, but upgrade to electric power trains.

I think I found my next Project!</description>
		<content:encoded><![CDATA[<p>As a car guy, I love your site. This is the future of hot rods. Restore not back to OE, but upgrade to electric power trains.</p>
<p>I think I found my next Project!</p>
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